Leetcode77组合
77组合
给定两个整数 n 和 k,返回 1 … n 中所有可能的 k 个数的组合。
示例:
输入: n = 4, k = 2
输出:
[
[2,4],
[3,4],
[2,3],
[1,2],
[1,3],
[1,4],
]
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/combinations 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
Solution 1
多叉树剪枝
class Solution:
def __init__(self):
self.result = None
self.stack = None
def combine(self, n: int, k: int) -> [[int]]:
if type(n) is not int or type(k) is not int:
raise Exception("Invalid input, must be int")
if n<=0 or k <=0:
raise Exception("Invalid input, must be positive")
if n < k:
raise Exception("n < k")
self.result = []
self.stack = []
for i in range(1, n+1):
self._recursiveGenarate(i, n, k)
return self.result
def _recursiveGenarate(self, start, end, k):
if (end - start + 1 < k):
return
if k == 1:
self.stack.append(start)
self.result.append(self.stack.copy())
self.stack.pop(-1)
else:
self.stack.append(start)
for i in range(start+1, end+1):
self._recursiveGenarate(i, end, k-1)
self.stack.pop(-1)
import java.util.*;
class Solution {
private List<List<Integer>> result;
private List<Integer> buffer;
Solution() {
}
public List<List<Integer>> combine(int n, int k) {
// exception conditions
// n,k is not int
// n<=0 || k <= 0
// n<k
result = new ArrayList<>();
buffer = new ArrayList<>();
for (int i = 1; i <= n; i++)
inorderTraversal(i, n, k);
return result;
}
private void inorderTraversal(int start, int end, int k) {
if (end + 1 - start < k)
return;
if (k == 1) {
buffer.add(start);
result.add(new ArrayList<>(buffer));
buffer.remove(buffer.size() - 1);
} else {
buffer.add(start);
for (int i = start + 1; i <= end; i++)
inorderTraversal(i, end, k - 1);
buffer.remove(buffer.size() - 1);
}
}
}