Leetcode181超过经理收入的员工

181超过经理收入的员工

SQL Schema

Create table If Not Exists Employee (id int, name varchar(255), salary int, managerId int)
Truncate table Employee
insert into Employee (id, name, salary, managerId) values ('1', 'Joe', '70000', '3')
insert into Employee (id, name, salary, managerId) values ('2', 'Henry', '80000', '4')
insert into Employee (id, name, salary, managerId) values ('3', 'Sam', '60000', 'None')
insert into Employee (id, name, salary, managerId) values ('4', 'Max', '90000', 'None')

表：Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
Id是该表的主键。
该表的每一行都表示雇员的ID、姓名、工资和经理的ID。

编写一个SQL查询来查找收入比经理高的员工。

以 任意顺序 返回结果表。

查询结果格式如下所示。

示例 1:

输入: 
Employee 表:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
输出: 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
解释: Joe 是唯一挣得比经理多的雇员。

Solution 1

题目的意思是，每个员工都对应一个经理，只比较员工工资与对应的经理的，而不是所有经理

--mysql # Write your MySQL query statement below
select A.name as `Employee` 
from `Employee` as A inner join `Employee` as B on A.managerId = B.id 
where A.salary > B.salary;